Question

draw a triangle pqr in which angle q=80,angle r=55,and angle qr=4.5cm.draw the perpendicular bisector of side qr
explain please

Answer 1

1.Draw a straight long line

2.Take a point Q on it and plot another point at a distance of 4.5cm and name it as point R

3.Keep the protractor on point Q and draw an angle of 80°

4.Keep the protractor on point R and draw an angle of 55°

5.Name the point of intersection of one arm of each angle as point P

6.Now take a compass and adjust it so that it's measure is more than half of segment QR

7.Place the pointer on Q and draw an arc above and below the segment, repeat the same procedure by keeping the pointer on R and try to intersect the arcs.

8.Now join the intersections of both of the arcs. The line formed would be the perpendicular bisector of seg QR.

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Answer 2

Step-by-step explanation:

Steps of construction:

1. Draw a line segment QR = 4.5 cm.

2. Draw ∠RQX = 80° and ∠QRY = 55°.

3. Let QX and RY intersect at P so that PQR is the required triangle.

4. With Q as center and radius more than 2.25 cm, draw arcs on either sides of QR.

5. With R as center and radius more than 2.25 cm, draw arcs intersecting the previous arcs at M and N.

6. Join MN

7. MN is the required perpendicular bisector of QR.