Question

draw a triangle pqr in which PQ is equal to 7 cm and QR is equal to 3 cm or P is equal to 4 cm is the construction of triangle possible

Answer 1

hey
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construction is not possible

given : PQ = 7cm
PR=4cm
QR=3cm

the sum of three sides of a ∆ is always greater than the third sides

4+3 = 7
7=7 (here sum of two sides is equal to third side)

7+3 = 10
10>4 (sum of two sides is greater than third)

4+7=11
11> 3 ( sum of two sides is greater than third)

hence all the cases are not true and construction is not possible

hope helped
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