draw a triangle PQR where angles are in the ratio 1:2:3. Draw triangle ABC similar to triangle PQR whose sides are 1/3 times the sides of the triangle PQR
Answers
A triangle PQR with angles in the ration 1:2:3 are given by 30°, 60°, 90°.
- we know that, sum of angles in triangle =180°
- given ration of angles = 1:2:3
- let the angles be =x
- then the ratio is given by,
- x+2x+3x=180°
- 6x=180
- x=30°
- 2x=60°
- 3x=90°
- Now,
- The triangle PQR is similar to triangle ABC, with the sides 1/3 times the sides of the triangle PQR.
- If side of triangle PQR, that is, QR=6cm, then the side of triangle ABC, that is ,BC=2cm.
Δ PQR & Δ ABC is constructed where angles are in the ratio 1:2:3
Step-by-step explanation:
draw a triangle PQR where angles are in the ratio 1:2:3.
∠P : ∠Q = ∠R ::: 1 : 2 : 3
∠P = y
=> ∠Q = 2y
=> ∠R = 3y
y + 2y+ 3y = 180°
=> 6y = 180°
=> y = 30°
∠P = 30° , ∠Q = 60° & ∠R = 90°
Step 1 : Draw a line segment of any length PQ
Step 2 : Draw an angle of 30° at P using Protector and draw a Ray Starting from P
Step 3 : Draw an angle of 30° at Q using Protector and draw a Ray Starting from Q
Step 4 : Mark intersection point of rays drawn in step 2 & 3 as R
Δ PQR is constructed
To Draw Δ ABC ≈ Δ PQR whose sides ar 1/3 times of ΔPQR
Step 1 : Draw an acute angle at PQ
Step 2 : Using compass take three points on angle drawn at equal distance consecutively
Step 3 : join 3rd point with Q as straight line using ruler
Step 4 :Using set square draw a line parallel to drawn in step 3 passing through 1st point and intersecting PQ at S
Step 5 : using compass measure PS
Step 6 : Draw a line segment AB = PS
Step 7 : Draw an angle of 30° at A using Protector and draw a Ray Starting from A
Step 8 : Draw an angle of 30° at B using Protector and draw a Ray Starting from B
Step 9 : Mark intersection point of rays drawn in step 7 & 8 as C
Δ ABC is constructed
Learn more:
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