Draw a triangle PQR with QR=7cm, Q=60,P=90, then construct a triangle aqc whose sides are 3/4 times the correspondings sides of triangle pqr
Answers
Given : QR = 7 cm, Q = 60°, P = 90°
To find : construct a triangle AQC whose sides are 3/4 times the corresponding sides of triangle PQR.
Solution:
Q = 60°, P = 90° => R = 30°
Step 1 : Draw a line segment QR = 7 cm
Step 2 : Using Protractor Draw angle of 60° at Q & 30° at R which meets at P
ΔPQR is Constructed
To Draw Δ AQC whose sides are 3/4 times the corresponding sides of triangle PQR.
Draw an acute angle at Q on PQ
Take 4 points at equal distance using compass from Q on angle drawn
Join 4th point with P
Draw a line parallel to line drawn in last step , passing through 3rd point & intersecting PQ at A
Draw an acute angle at Q on RQ
Take 4 points at equal distance using compass from Q on angle drawn
Join 4th point with R
Draw a line parallel to line drawn in last step , passing through 3rd point & intersecting RQ at C
Join AC
ΔAQC is 3/4 times of ΔPQR
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