Question

Draw a triangle whose sides
whose sides are 6cm . 8cm and 10cm
construct the incircle of the triangle​

Answer 1

Answer:

Hey ...

steps to constrution :-

• Draw a line segment AB = 10cm

• Using measures AC = 8cm and BC = 6 cm , draw a triangle .

• Now make an acute angle taking A as centre .

• Mark 5 points A1 , A2 , A3 , A4 and A5 , such that A1 = A2 = A3= A4 = A5 .

• Join A5B .

• Draw A3B' || A5B

• Draw B'C' || BC

• Hence , AB'C' is the required triangle .

The figure is in the given attachment....

Hope it helped you dear....

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Answer 2

Answer:

Hey ...

steps to constrution :-

• Draw a line segment AB = 10cm

• Using measures AC = 8cm and BC = 6 cm , draw a triangle .

• Now make an acute angle taking A as centre .

• Mark 5 points A1 , A2 , A3 , A4 and A5 , such that A1 = A2 = A3= A4 = A5 .

• Join A5B .

• Draw A3B' || A5B

• Draw B'C' || BC

• Hence , AB'C' is the required triangle .

Step-by-step explanation:

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