Question

Draw a triangle with AB=6cm angleA=45 angle B=135

Answer 1

Answer:

Step-by-step explanation:

Draw a base line and label the left end A. From A strike a vertical, then bisect the right angle formed at A

Draw a line 6cm long on the bisector, and label the end B. From B strike a vertical to intersect the base line at D.

You now have a right isosceles triangle ABD with a hypotenuse length of 6cm. Using Pythagoras work out the vertical line length BD.

This is 4.24264 (sqrt 18). The next angle you need is the 75 deg line from B to the base line.

The angle ABD is 45 deg, subtracted from 75 deg = 30 deg.

Using trigonometric tables, find secant 30 and multiply by the length of side BD. This equals 4.89898 (sqrt 24).

Set your protractor to 4.89898 and strike an arc to intersect the base line and label this C.

There is your triangle. Incidentally,

the base line AC is equal to (sqrt 18) + (sqrt 7).

Answer 2

Answer:

Step-by-step explanation:

Draw a base line and label the left end A. From A strike a vertical, then bisect the right angle formed at A

Draw a line 6cm long on the bisector, and label the end B. From B strike a vertical to intersect the base line at D.

You now have a right isosceles triangle ABD with a hypotenuse length of 6cm. Using Pythagoras work out the vertical line length BD.

This is 4.24264 (sqrt 18). The next angle you need is the 75 deg line from B to the base line.

The angle ABD is 45 deg, subtracted from 75 deg = 30 deg.

Using trigonometric tables, find secant 30 and multiply by the length of side BD. This equals 4.89898 (sqrt 24).

Set your protractor to 4.89898 and strike an arc to intersect the base line and label this C.

There is your triangle. Incidentally,

the base line AC is equal to (sqrt 18) + (sqrt 7).