Question

Draw a triangle with base QR=6cm and angles are in the ratio 3:4:5​

Answer 1

Use Angle Sum Property of Triangle

Step-by-step explanation:

Draw a triangle with base QR = 6 cm and angles are in the ratio 3:4:5

Let the angle represented be x

So, $\angle P$ = 3x

$\angle Q$ = 4x

$\angle R$ = 5x

As per the angle sum property of triangle,

Sum of angles of triangles is equal to 180 °

Now, adding P, Q & R angles,

3x + 4x + 5x = 180

12x = 180

x = 15

So, $\angle P = 3 \times 15 = 45$°

$\angle Q = 4 \times 15 =60$°

$\angle R = 5 \times 15 = 75$°

Steps of construction-

1.) QR = 6 cm is the line segment drawn initially.

2.) Draw $\angle PQR = 60$°, with center as Q

3.) Draw $\angle QRP = 75$°, with center as R

4.) The intersecting point of $\angle PQR\ and\ \angle QRP$ is marked as P.

The required triangle ΔPQR is Constructed.