draw a two radie in a circle of radius 3.5cm having an angle 100 degree at the centre construct tangents at the end points of the radie?
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Step first : Take a point O on the plane and draw a circle of radius OA = 3.5 cm
Step second : Draw a ∠AOB = ∠AOC = 30° at O.
Step third: Draw a BX ⊥ OB and CX ⊥ OC at B and C respectively. BX and CS intersects at X.
Here,
BX and CX are two tangents Angele to the circle inclined to each other at 120°.
justification:
∠XOB = 30°
∠OBX = 90°
In ΔBOX,
∠XOB + ∠OBX + ∠BXO = 180°
∴ 30° + 90° + ∠BXO = 180°
⇒ ∠BXO = 180° – 120° = 60°
Similarly, ∠CXO = 60°
∴ ∠BXC = ∠BXO + ∠CXO = 60° + 60° = 120°
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@Dawood
HOPE SO IT WILL HELP.....
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