Question

Draw a velocity-time graph for a ball thrown upwards at a velocity of 10m/s, taking g as 10m/s2

Answer 1

Answer:

Initial velocity of the ball        u=100 m/s

Acceleration of the ball        a=−g=−10  m/s2

Using          v=u+at

∴     v=100−10t

Thus v−t graph is a straight line intersecting the t axis at  t =10 s

Also       v∣∣∣∣∣t=15=100−10(15)=−50    m/s2

Height (displacement) of the ball is equal to the area under the curve during   0<t<15

∴    h=21×100×10−21×(15−10)×50=375  m

Explanation:

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Answer 2

Given :-

• Initial velocity (u) = 10 m/s

• Acceleration due to gravity (g) = 10 m/s²

Plotting V vs t graph :-

• Time of ascent = u/g = 1 sec

• At highest point, v = 0 (at 1 sec)

• Time of descent = u/g = 1 sec

So, Graph is as shown in attachment.