Question

Draw a velocity-time graph for the following data:
Time (in
seconds
)

2 4 6 8 10 12 14

Velocity
(in m/s)

5 10 15 20 20 10 0

(a) What type of motion is represented during 0-6 seconds?
(b) What is acceleration in the first 6 seconds?
(c) Calculate the retardation (i.e negative acceleration) during 12-14 seconds.

Answer 1

Answer:

(a) During the 0 -6 seconds the motion represented is uniform motion .

(b) Acceleration in first 6 seconds = a = (15-5) / (6 -2 ) = 10/4 = 2.5 m/s2 .

(c) Distance travelled between the 6 to 8 seconds is ,

S=ut+12ft2=(15×2)+12×(20−152)×4=30+5=35 mS=ut+12ft2=15×2+12×20-152×4=30+5=35 m

(d) Retardation = a' = ( 0-10)/2 = - 5 m/s2

Answer 2

Answer:

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