Question

Draw ∆ ABC, if angle B is 90 degree, AB = BC and AB +AC =10.3 cm .

Answer 1

Steps of Construction:1. Draw the base BC = 7 cm.2. At the point B make an angle XBC = 75°.3. Cut a line segment BD equal to AB + AC ...

Answer 2

Hope u like my process
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Given,
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A right angled triangle,

=> Angle ABC = 90

=> AB =BC
i.e. Perpendicular = base.

=> AB+AC =10.3

AC (Hypotenuse) = 10.3 - AB

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NOW,
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By Pythagoras theorem
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=>( AC) ² = (AB) ² + (BC) ²

or, (10.3 - AB) ² = (AB) ² +(AB) ²

or, (10.3)² - 2×10.3×AB +(AB) ² = 2(AB)²

or, (AB)² + 20.6AB - 106.09 = 0

or,
$or. \: \: ab = \frac{ - 20.6 + \sqrt{ {20.6}^{2} - 4 \times 1 \times (- 106.09)} }{2} \\ \\ or. \: \: ab = \frac{ - 20.6 + \sqrt{842.72} }{2} \\ \\ or. \: \: ab = \frac{ - 20.6 + 29.1 3}{2} = \frac{8.53}{2} = 4.26$
Now,

AC = 10.3-AB = 10.3-4.26=6.04

And AB=BC = 4.26
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