draw∆ABC in which l(AB)=5•5cm ,l(BC)=4•2cm,l(AC)=3•5cm
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Step-by-step explanation: 1) draw a line BC of lenght 4.2cm
2)take a divider and take a distance of 5.5cm and place it on point B and make an arc. mark it as point A.
3)from point A take a distance of 3.5cm on the divider and place it on point C and make an arc connecting point A.
4) triangle ABC is ready
Below is an attachment of the triangle ABC
Thank you !!!!
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