Question

Draw ∆ABC such that BC=6.5cm ; AB=5.2cm. AC=5.8cm. contruct a perpendicular bisector for seg BC?

Answer 1

Step-by-step explanation:

Draw a bc line 6.5cm

contruct AB 5.2cm

contruct AC=5.8cm

Answer 2

Step-by-step construction:

First we need to construct a triangle

• Draw the base BC of the triangle of the length 6.5 cm

• Then take the compass and adjust it to a radius of 5.2 cm

• From the point B draw an arc with the compass

• Take the compass and adjust the radius to 5.8 cm

• From point C draw an arc with the compass

• Both these arcs intersect at a point and this can be labelled A

Then we construct perpendicular bisector of segment BC

• From B with any radius of compass draw an arc

• From C with the same radius draw an other arc

• Both these arcs coincide at two points on either sides of BC

• Join both of them to obtain a straight perpendicular line

• This is the perpendicular bisector of BC