Question

Draw ∆ABC with AB = 6cm, ∠A = 221/2o, ∠B =67 /2

Answer 1

Step-by-step explanation:

Draw horizontal line is AB of 6 cm. Now make anle of 45° at. A . Draw the angle bisector of

45° angle from A. Let this angle bisector is AP.

The length of line segment Ap should be more than 6cm. Now from the mid point of AB draw the circle of radius 3 cm. Mark the point at which this circle cuts the line segment AP as C. Join BC. Now triangle ABC is the triangle having AB = 6 cm ,< A = 22 1/2° ,< B = 67 1/2° .