draw ac=ab+dc.where ab =5.5cm,dc=7.5cm
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Answer:
It is given that ,
In ∆ABC,
AB = 5.5 cm ,
AC = 7.5 cm ,
BC = 6.5 cm
Construction steps :
1 ) Draw AB = 5.5 cm line segment.
2 ) Take A and B as centers and 7.5 cm
and 6.5 cm as radii respectively draw
two intersecting arc's . Intersecting point
is C .
3 ) Join C to A and B .
Required Scalene ∆ ABC formed.
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Answer:
Answer: 27x^3 +1/x^3 + 27x + 9/x Σ R Step-by-step explanation: Formula used : (a + b)^3 = a^3 + b^3 + 3ab( a + b) Here, (3x + 1/x)^3 (3x)^3 + (1/x)^3 + 3(3x*1/x)(3x+1/x) 27x^3 +1/x^3 + 3(3*1)(3x+1/x) → 27x^3 +1/x^3 + 9(3x+1/x) → 27x^3 +1/x^3 + 27x + 9/x Therefore, (3x + 1/ x)^3 = 27x^3+1/x^3 +27x + 9/x
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