Draw an acute angle triangle PQR, draw 3 altitudes of triangle PQR and name point of concurrence of altitude O....
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Join PA that intersect QR at L. So, PL is the altitude on side QR. In the same manner, draw QM⊥PR and RN⊥PQ. Hence, ∆PQR is the required triangle with altitudes PL, QM and RN on sides QR, RP and PQ respectively with O as the point of concurrence of all the three altitudes.
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