Draw an angle of measure 147° and construct its bisector
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teps of construction:
(a) Draw a ray OA.
(b) With the help of protractor, construct ∠AOB = 147 degree.
(c) Taking centre O and any convenient radius, draw an arc which intersects the arms OA bar and OB bar at P and Q respectively.
(d) Taking P as centre and radius more than half of PQ, draw an arc.
(e) Taking Q as centre and with the same radius, draw another arc which intersects the previous at R.
(f) Join OR and produce it.
Thus, OR bar is the required bisector of ∠AOB.
(a) Draw a ray OA.
(b) With the help of protractor, construct ∠AOB = 147 degree.
(c) Taking centre O and any convenient radius, draw an arc which intersects the arms OA bar and OB bar at P and Q respectively.
(d) Taking P as centre and radius more than half of PQ, draw an arc.
(e) Taking Q as centre and with the same radius, draw another arc which intersects the previous at R.
(f) Join OR and produce it.
Thus, OR bar is the required bisector of ∠AOB.
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