draw an angle of measure 153 degree and divide it into four equal parts. also write the steps of construction
Answers
1.Draw a ray BC
2.Place center of the protractor on point B, and coincide line BC and protractor line.
3.Mark point A on 153∘
4.Join AB
∴∠ABC=153∘
5.Mark points D and E where arc intersects AB and BC
6.Now, taking D and E as centers and with the radius more than 21DE, draw arcs to intersect each other.
7.Let them intersect at point X
8.Join B and X
∴BX is bisector of ∠ABC=153∘
9.Mark point F where BX intersects the arc
10.Now, taking E and F as centers and with the radius more than 21EF, draw arcs to intersect each other.
11.Let them intersect at point Y
12.Join B and Y
∴BY is bisector of ∠ABX
Now we draw bisector of ∠CBX
13.Taking D and F as centers and with the radius more than 21DF, draw arcs to intersect each other.
14.Let them intersect at point Z
15.Join B and Z
∴BZ is bisector of ∠CBX
Thus, we have divided 153∘ in to 4 equal parts.
I hope my answer would help u...❤
