Physics, asked by ScienceisLife1, 8 months ago

Draw an energy vs ht/ distance graph to prove law of conservation of energy for
1) Freely falling body
2) An elastic spring

It's urgent. Plzx​

Answers

Answered by nirman95
1

To draw:

Energy vs ht/ distance graph to prove law of conservation of energy for

  • Freely falling body

  • An elastic spring

For a freely falling body , the kinetic energy decreases and proportionately the potential energy increases , such that the net mechanical energy remains constant.

Similarly , for a body on an elastic spring , the potential energy of the spring increases with proportionate decrease in the kinetic energy of the body. This leads to constant it net mechanical energy of the body.

Graph:

\boxed{\setlength{\unitlength}{1cm}\begin{picture}(6,6)\put(1,1){\vector(1,0){3}}\put(1,1){\vector(0,1){3}}\put(1,3){\line(1,0){2}}\put(4.5,1){h}\put(0.75,4.25){$E_{g}$}\put(1,0.5){Energy\:of\:free\:falling\:body}\end{picture}}

\boxed{\setlength{\unitlength}{1cm}\begin{picture}(6,6)\put(1,1){\vector(1,0){3}}\put(1,1){\vector(0,1){3}}\put(1,3){\line(1,0){2}}\put(4.5,1){x}\put(0.75,4.25){$E_{s}$}\put(1,0.5){Energy\:of\:body\:on\:Spring}\end{picture}}

Equations:

For free-falling body in gravity:

\boxed{\sf{\dfrac{1}{2}m{v}^{2}+mgh=constant}}

For body on spring:

\boxed{\sf{\dfrac{1}{2}m{v}^{2}+\dfrac{1}{2}k{x}^{2}=constant}}

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