draw an equilateral triangle of side 5 cm? draw a right angled triangle of the same area with the base 5 cm ?
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Answers
Answer:
Steps of construction of a triangle:
1. Draw a line segment BC of length 5cm.
2. Measure distance of 5 cm in compass. Taking B as center draws an arc.
3. Taking C as center with the same distance i.e. 5 cm draws another arc in such a way that intersects the first arc we drew.
4. Both the arcs intersect each other; name that point of intersection as A.
5. Now join the point AB and AC to formed the triangle
6. Required triangle ABC is drawn as an equilateral triangle because all the sides are equal.
Area of ABC can be calculated using the formula of equilateral triangle i.e. A=3–√a24
Area of △ABC=3–√a24 (Here a is the side of equilateral triangle i.e. 5 cm)
By putting the value of ‘a’ we get,
Area of △ABC=3–√a24=3–√×5×54=10.82cm2
Now we have to construct a square whose area is the same as a triangle. To solve this we have to equate the area of the square with the area of the triangle.
As we know the area of the square is(side)2. So after equating we get,
(side)2=10.82cm2⇒side=10.82cm2−−−−−−−−√
∴Side =3.28 cm.
By the help of this side we construct our square.
Steps of Construction for square:
1. Draw segment BC of length 3.28 cm.
2. Draw a line perpendicular on BC through B by the help of a protector.
Measure a distance of 3.28 cm in compass and cut this line at point A taking B as centre.
3. Draw a line perpendicular to BC through C by the help of a protector..
Measure a distance of 3.28 cm in compass and cut this line at point D taking C as a centre.
4. Join AB, CD and AD.
5. Required square ABCD is drawn.
Answer:
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