Question

Draw an equilateral triangle PQR with each side equal to 8.2 cm.
struct the perpendiculars to the sides from the opposite vertices
What do you notice about these perpendiculars?​

Answer 1

Steps of construction:

1. Draw a line segment QR = 8 cm.
2. Taking Q as a centre and radius 8 cm, draw an arc above QR.
3. With same radius and centre R , draw an arc which cut the previous arc at P.
4. Join PQ and PR.
5. Hence PQR is the required triangle.

After Drawing the perpendiculars to the sides from the opposite vertices we noticed That:

• The bisectors of angles ,sides,edges and circumcentre and incentre are the mid points of triangle

Figure of Equilateral triangle

$\\\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){ \bf A }\put(0.5,-0.3){ \bf C }\put(5.2,-0.3){ \bf B }\end{picture}$

Answer 2

Answer:

please mark as brailiest if u are satisfied....

Step-by-step explanation:

raw a line segment QR = 8 cm.

Taking Q as a centre and radius 8 cm, draw an arc above QR.

With same radius and centre R , draw an arc which cut the previous arc at P.

Join PQ and PR.

Hence PQR is the required triangle.

After Drawing the perpendiculars to the sides from the opposite vertices we noticed That:

The bisectors of angles ,sides,edges and circumcentre and incentre are the mid points of triangle

\\\\

Figure of Equilateral triangle