Question

Draw an equilateral triangle whose altitude is 6 cm

Answer 1

Step-by-step explanation:

(i) Draw a line XY.

(ii) Construct perpendicular PD at any point D on the line XY.

(iii) From point D, cut-off line segment AD = 6 cm.

(iv) Construct ∠BAD = ∠CAD = 30°. Then ABC is the required triangle.

Justification

As ∠A = ∠BAD + ∠CAD = 30 °+ 30° = 60° and AD perpendicular BC therefore, △ABC is an equilateral triangle with altitude AD = 6 cm.

Hope it Helps...........U

Answer 2

Answer:

*Refer the attachment.