Question

draw an isocles triangle of same area with base bc=6cm​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

Step I : Draw BC = 6 cm. Step II: Construct XY, the perpendicular bisector of line segment BC, meeting BC at M. Step III: Along MP, cut-off MA = 4 cm. Step IV: Join BA and CA. Then △ABC so obtained is the required △ABC. Step V: Extend BC to D, such that BD = 9 cm (=3/2 x 6 cm). Step VI: Draw DE || CA meeting BA produced at E. Then △EBD is the required triangle. Justification: Since DE || CA △ABC ~ △EBD and EB/AB = DE/CA = BD/BC =9/6 =3/2 Hence, we have the new triangle similar to the given triangle whose sides are 3/2 times the corresponding sides of the isosceles △ABC.

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