Question

draw an Isosceles triangle ABC in which AB=AC draw median from A on BC and also altitudes from A on BC are median or altitude same here

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Answer 1

Step-by-step explanation:

There is your answer in the attachment!

Answer 2

Answer:

Solution

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In ΔABP and ΔACP,

∠APB=∠APC (Both equal to 90°)

AB=AC [∵ΔABC is an isosceles triangle.]

AP=AP (Common Side)

By R.H.S. criterion of congruence,

△ABP≅△ACP

⇒∠B=∠C (CPCT)