Draw an isosceles triangle ABC with AB = AC and base BC = 7 cm and vertical angle is 120°. Construct triangle AB´C´ ~ triangle ABC with its sides 1 1/ 3 times of the corresponding sides of triangle ABC.
Answers
An isosceles ΔABC is constructed with AB = AC and base BC = 7 cm and vertical angle is 120°
Step-by-step explanation:
BC = 7 cm
AB = AC
=> ∠B = ∠C
∠A = 120°
∠A + ∠B + ∠C = 180°
=> ∠B + ∠C = 60°
∠B = ∠C = 30°
Step 1 : Draw a line segment BC = 7 cm using ruler
Step 2: Draw an angle of 30° at B on BC using protector
Step 3: Draw an angle of 30° at C on BC using protector such that it intersect angle drawn in step 2 at A
ΔABC is constructed
AB' = 1 1/3 = 4/3 times of AB
Step 1 : Extend line AB
Step 2 : Draw an acute angle at A on AB
Step 3 : Take 4 point one by one consecutively at equal distnace on angle drawn from A
Step 4 : Join 3rd point with B
Step 5 : Draw a line parallel to line drawn in step 4 , passing through 4th point & intersecting extended AB at B'
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