draw an isosceles triangle pqr in which PQ is equal to p r is equal to 6 centimetre and QR is equal to 5 cm construct a triangle ABC similar to Triangle pqr in which a b is equal to 8 cm give the justification of the construction
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According to question
given that
PQ = PR = 6 Cm
and QR = 5 Cm
Draw a perpendicular from P to S on side QR
So QS = SR = 5/2 = 2.5 Cm
So PS^2 = PR^2 - SR^2
PS^2 = 36 - 25/4
PS^2 = 119/4
So PS = root 119 /2
Thus Area of triangle PQR = 1/2 * QR * PS
= 1/2 * 5 * root 119 / 4
= 5/8 root 119
Similarly Area of triangle ABC = 5/8 root 119
given that
PQ = PR = 6 Cm
and QR = 5 Cm
Draw a perpendicular from P to S on side QR
So QS = SR = 5/2 = 2.5 Cm
So PS^2 = PR^2 - SR^2
PS^2 = 36 - 25/4
PS^2 = 119/4
So PS = root 119 /2
Thus Area of triangle PQR = 1/2 * QR * PS
= 1/2 * 5 * root 119 / 4
= 5/8 root 119
Similarly Area of triangle ABC = 5/8 root 119
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