draw an isosceles triangleABC in which BC =5.5cm and altitude AL = 3cm then construct a triangle whose sides are 3/4 of the corresponding sides of triangleABC with steps of construction
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Steps of construction.
1. Draw a lline segment AB = 6cm.
2. Draw a perpendicular bisector DX of AB which cuts it at D.
3. Cut a ray of 4cm on a ray DX and name it third vertex C of this isosceles triangle ABC.
4. Draw an acute angle BAY.
5. Cut ray AY in 4 equal parts A1, A2, A3, A4A1, A2, A3, A4.
6. Join A4BA4B.
7. Draw a line parallel to A4BA4B through A3A3 which cuts AB at B'.
8. Draw a line parallel to BC through B' which cuts AC at C'.
9. This is required Triangle AB'C'. hope it help......
1. Draw a lline segment AB = 6cm.
2. Draw a perpendicular bisector DX of AB which cuts it at D.
3. Cut a ray of 4cm on a ray DX and name it third vertex C of this isosceles triangle ABC.
4. Draw an acute angle BAY.
5. Cut ray AY in 4 equal parts A1, A2, A3, A4A1, A2, A3, A4.
6. Join A4BA4B.
7. Draw a line parallel to A4BA4B through A3A3 which cuts AB at B'.
8. Draw a line parallel to BC through B' which cuts AC at C'.
9. This is required Triangle AB'C'. hope it help......
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