Question

Draw and explain with the help of a well labelles diagram the conduction of electricity in ionic copmpound?

Answer 1

Hey buddy don't get confused by the diagram ,I will give you point wise explanation.

• Electrolyte used in this process : Molten lead bromide (pbBr2).
• Electrodes : Graphite rods .

[Note: Graphite rods are used because they are inert. ]

• Ions present : Pb2+ ions(cations) and Br- (anions) ; lead ions and Bromide ions.
• Electrode reactions:

1. At cathode: Pb2+ + 2e- gives Pb
2. At anode: Br- - 1 e- gives Br

Br +Br gives Br2(negative Bromide ions come in contact with the anode, give an electron each and become bromine atoms. These two atoms combine to form bromine molecule)

• The overall reaction at electrodes: PbBr2(l) gives Pb(s) + Br2(g)
• Observations :

1. Dark reddish brown fumes of bromines evolve at the anode.
2. Silvery grey metal lead is formed on the cathode.

Buddy hope this will help u........

Only this is enough to study If u r an ICSE student .Reduced Syllabus.

Answer 2

Answer:

Electrolyte used in this process : Molten lead bromide (pbBr2).

Electrodes : Graphite rods .

[Note: Graphite rods are used because they are inert. ]

Ions present : Pb2+ ions(cations) and Br- (anions) ; lead ions and Bromide ions.

Electrode reactions:

At cathode: Pb2+ + 2e- gives Pb

At anode: Br- - 1 e- gives Br

Br +Br gives Br2(negative Bromide ions come in contact with the anode, give an electron each and become bromine atoms. These two atoms combine to form bromine molecule)

The overall reaction at electrodes: PbBr2(l) gives Pb(s) + Br2(g)

Observations :

Dark reddish brown fumes of bromines evolve at the anode.

Silvery grey metal lead is formed on the cathode.

Explanation: