draw and prove that opposite angles of a paralelogram are equal
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Here, ABCD is a parallelogram with AC as its diagonal.
We know, in parallelogram opposites sides are parallel.
So, AB∥DC and AD∥BC
Since, AB∥DC and AC is the transversal
⇒ ∠BAC=∠DCA ---- ( 1 ) [ Alternate angles ]
Similarly, AD∥BC and AC is the transversal.
⇒ ∠DAC=∠BCA ---- ( 2 ) [ Alternate angles ]
Adding ( 1 ) and ( 2 ),
⇒ ∠BAC+∠DAC=∠DCA+∠BCA
⇒ ∠BAD=∠DCB
Similarly, we can prove, ∠ADC=∠ABC
∴ We have proved that, opposite angles of a parallelogram are equal.
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