Question

Draw Angle PQR of measure 70° such that QP = 5 cm and QR = 4.5 cm. Through R, draw a line parallel to QP and through P draw a line parallel to QR intersecting each
other at O. Measure OP and OR. Write Steps of Constructions also.

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Answer 1

Step-by-step explanation:

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• ⇒ We know that opposite sides and angle of parallelogram are equal.
• ⇒ And adjacent angles of parallelogram are supplementary. By using these properties we are going to construct a parallelogram.
• ⇒ Draw a line segment PQ=5cm
• ⇒ Construct an angle of 70° at point Q.
• ⇒ Cut off QR=4cm
• ⇒ Construct an angle of 110° at point P.
• ⇒ Cut off PS=4cm
• ⇒ Join RS
• ⇒ Thus PQRS is a required parallelogram
• ⇒ Let a=5cm and b=4cm
• ⇒ Perimeter of parallelogram PQRS=2(a+b) =2(5+4)=18
• ⇒ The perimeter of parallelogram PQRS=18cmk

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Answer 2

Answer:

thanks for free points.......