Draw Angle PQR of measure 70° such that QP = 5 cm and QR = 4.5 cm. Through R, draw a line parallel to QP and through P draw a line parallel to QR intersecting each
other at O. Measure OP and OR. Write Steps of Constructions also.
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⇒ We know that opposite sides and angle of parallelogram are equal.
⇒ And adjacent angles of parallelogram are supplementary. By using these properties we are going to construct a parallelogram.
⇒ Draw a line segment PQ=5cm
⇒ Construct an angle of 70 ∘at point Q.
⇒ Cut off QR=4cm
⇒ Construct an angle of 110∘ at point P.
⇒ Cut off PS=4cm
⇒ Join RS
⇒ Thus PQRS is a required parallelogram
⇒ Let a=5cm and b=4cm
⇒ Perimeter of parallelogram PQRS=2(a+b) =2(5+4)=18
⇒ The perimeter of parallelogram PQRS=18cm
Hope it helps....☺
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