Math, asked by renu23674, 5 months ago

Draw Angle PQR of measure 70° such that QP = 5 cm and QR = 4.5 cm. Through R, draw a line parallel to QP and through P draw a line parallel to QR intersecting each
other at O. Measure OP and OR. Write Steps of Constructions also.

plz no irrelevant answer​ , NO SPAMMING ​

Answers

Answered by Anonymous
5

Refer The Above Attachment

⇒ We know that opposite sides and angle of parallelogram are equal.

⇒ And adjacent angles of parallelogram are supplementary. By using these properties we are going to construct a parallelogram.

⇒ Draw a line segment PQ=5cm

⇒ Construct an angle of 70 ∘at point Q.

⇒ Cut off QR=4cm

⇒ Construct an angle of 110∘ at point P.

⇒ Cut off PS=4cm

⇒ Join RS

⇒ Thus PQRS is a required parallelogram

⇒ Let a=5cm and b=4cm

⇒ Perimeter of parallelogram PQRS=2(a+b) =2(5+4)=18

⇒ The perimeter of parallelogram PQRS=18cm

Hope it helps....

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