draw any three figure of triangle having ratio of area of triangle is 1
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If two triangles are similar, then the ratio of the area of both triangles is proportional to square of the ratio of their corresponding sides.
To prove this theorem, consider two similar triangles ΔABC and ΔPQR
According to the stated theorem
ar△PQRar△ABC=(PQAB)2=(QRBC)2=(RPCA)2
Since area of triangle =21×base×altitude
To find the area of ΔABC and ΔPQR draw the altitudes AD and PE from the vertex A and P of ΔABC and ΔPQR
Now, area of ΔABC =21×BC×AD
area of ΔPQR =21×QR×PE
The ratio of the areas of both the triangles can now be given as:
ar△PQRar△ABC=21×QR×PE21×BC×AD
ar△PQRar△ABC
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