Draw CD 1 AB, A-D-B
sest is median of A ABC
= BM -- (i)
Point C is the common vertex of A AMC & A BMC
The height of two triangles is equal
A (A AMC)
(Triangle having equal height)
A (A BMC)
(from (i))
А A
A (A AMC)
A (A BMC)
Answers
Answered by
0
Answer:
right
Step-by-step explanation:
by AA criteria we can use Pythagoras theorem
Similar questions