Question

draw circle of radius 3.8 CM. Draw any two of its chord .Construct a perpendicular bisector of these chords .Where do they intersect?

Answer 1

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Answer 2

Answer: To draw a circle of radius 3.8 cm, follow these steps:

1. Take a compass and set its width to 3.8 cm.
2. Place the pointed end of the compass on a piece of paper and draw a circle by rotating the compass around its fixed end.
3. Label the center of the circle as point O.

Step-by-step explanation: To draw two chords of the circle, follow these steps:

• Place the compass on point O and draw two lines that intersect the circle on opposite sides. These lines will be chords of the circle.

• Label the points where the chords intersect the circle as A, B, C, and D.
• To construct the perpendicular bisector of these chords, follow these steps:
• Draw a line connecting points A and B, and another line connecting points C and D.
• Find the midpoint of line AB and label it as point P.
• Find the midpoint of line CD and label it as point S.

• Draw a line passing through points M and N. This line is the perpendicular bisector of chords AB and CD.

The perpendicular bisectors of two chords of a circle intersect at the center of the circle. Therefore, the perpendicular bisector of chords AB and CD intersects at point O, which is the center of the circle.

To know more chords click the link below:

https://brainly.in/question/8131250

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