Draw cis and trans- isomers of 1,3-cyclobutanedicarboxylic acid. Comment on the
dipole moment of these isomer
Answers
Explanation :
The cis-isomer and trans-isomer of 1,3-cyclobutanedicarboxylic acid are shown below.
Dipole moment : It measure the net polarity in a molecule.
As we know that the geometrical symmetry of the molecule and the polarity of the bonds both are equally important for determining the polarity of the molecule.
The molecule that has zero dipole moment that means it is a geometrical symmetric molecule and the molecule that has some dipole moment that means it is a geometrical asymmetric molecule.
As the molecule is symmetric, the dipole moment will be zero and the molecule will be non-polar.
As the molecule is asymmetric, the dipole moment will not be zero and the molecule will be polar.
The compound having two same functional groups occupying the adjacent position to each other is called cis-isomer while that in which the two same functional groups occupying the opposite position to each other is called trans-isomer.
As the two functional groups occupying the opposite position. So, their dipole cancel out each other. The net dipole moment will be zero.
As the two functional groups occupying the adjacent position. So, their dipole will not be cancel out each other. The net dipole moment will not be zero.
