Question

draw/construct 45°
step by step tell??​

Answer 1

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$\rightsquigarrow$ :Draw a ray OA

$\rightsquigarrow$  :Take O as a centre with any radius, draw an arc DCB is that cuts OA at B.

$\rightsquigarrow$ :With B as a centre with the same radius, mark a point C on the arc DCB.

$\rightsquigarrow$  :With C as a centre and the same radius, mark a point D on the arc DCB.

$\rightsquigarrow$ :Take C and D as centre, draw two arcs which intersect each other with the same radius at P.

$\rightsquigarrow$  :Finally, the ray OP is joined which makes an angle 90° with OP is formed.

$\rightsquigarrow$ :Take B and Q as centre draw the perpendicular bisector which intersects at the point R

$\rightsquigarrow$ :Draw a line that joins the point O and R

$\rightsquigarrow$ :So, the angle formed ∠ROA = 45°

Answer 2

1. Draw a ray AB.
2. Then, make a point O on the ray AB.
3. Draw a semi-circle from that point O with any radius.
4. With the same-radius draw an arc from the left point where arc and ray intersect. Let it be C.
5. Draw an arc from the arc drawn in step 4. Let it be marked as D.
6. Draw an arc from both the arcs drawn in step 4&5
7. Let it be intersect at E. Draw a line from point O to it. This is 90°
8. Then, from the right point where arc and ray AB intersect, draw an arc. Let it be marked as G.
9. Draw an arc from the point where 90° and the semi-circle intersect. Let it be F .
10. Let the two arcs intersect at I. Draw a line from point O to I. This is 45°.

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