Question

draw draw a line segment of length 8.2 cm and construct its perpendicular bisector​

Answer 1

Answer:

steps:

*Draw a line segment AB of 8.2cm.

*Now take arc from A to upside and downside from taking more than half distance of AB.

*Similarly take arcs from B without changing the distance of compass.

*Now join the intersection of arcs to draw perpendicular bisector of AB

Answer 2

$\large\sf\underline{Question\::}$

Draw a line segment of length 8.2 cm and construct its perpendicular bisector

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‎ $\large\sf\underline{Perpendicular\:bisector\::}$

The line drawn perpendicular through the mid point of a given line segment is called the perpendicular bisector of the line segment.

To construct a perpendicular bisector of a line segment we need the following instruments :

• Ruler

• Compass

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$\large\sf\underline{Construction\::}$

$\dag\:\underline{\sf Step \: 1\::}$

Draw a line segment of length 8.2cm with the help of a scale and name the two points as A and B.

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$\dag\:\underline{\sf Step \: 2\::}$

Now taking A as a centre and radius more than half of the length of AB , we need to draw two arcs of same length one above AB and one below AB.

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$\dag\:\underline{\sf Step \:3\::}$

With the same radius and B as a centre we need to draw two arcs to cut the already drawn arcs in Step 2 . Let's mark the intersection of the arcs as C and D.

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$\dag\:\underline{\sf Step \:4\::}$

Join C and D.

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${\sf{{\green{CD\:is\:the\:required\:perpendicular\:bisector\:of\:AB}}}}$

$\sf\:AO=OB=\cancel{\frac{8.2}{2}}=4.1\:cm$

$\sf\:and\:∠AOC=90°$

‎ $\large\sf\underline{Note\::}$

A perpendicular is a line that meets another line at an angle of 90°

Here CD meets AB at an angle 90°

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!! Hope it helps !!

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