draw equilateral triangle ABC , l(AB)=l(BC)=l(AC)= 5.7cm
Answers
(1) 5.3 cm
Steps of construction:
1. Draw line segment AB = 5.3 cm.
2. With A as centre and radius more than half of AB, mark two arcs, one above and other below the line AB.
3. With B as centre and same radius, draw two arcs cutting the previous drawn arcs and name the point of intersection as X and Y.
4. Join XY and name the point where this line cuts AB as point P.
XY is the perpendicular bisector of AB.
(2) 6.7 cm
Steps of construction:
1. Draw line segment CD = 6.7 cm.
2. With C as centre and radius more than half of CD, mark two arcs, one above and other below the line CD.
3. With D as centre and same radius, draw two arcs cutting the previous drawn arcs and name the point of intersection as A and B.
4. Join AB and name the point where this line cuts CD as point Q.
AB is the perpendicular bisector of CD.
(3) 3.8 cm
Steps of construction:
1. Draw line segment XY = 3.8 cm.
2. With X as centre and radius more than half of XY, mark two arcs, one above and other below the line XY.
3. With Y as centre and same radius, draw two arcs cutting the previous drawn arcs and name the point of intersection as A and B.
4. Join AB and name the point where this line cuts XY as point R.
AB is the perpendicular bisector of XY.
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