Question

Draw fixture of 18 teams on knockout basis. Consider two teams are seeded...

Answer 1

Draw a fixture of 18 teams based on knockout basis we should first calculate the number of bye

Explanation:

• the number of bye is the difference between the higher exponent of two with the number of teams that are playing in the tournament. In this case the number of bye is equal to 2⁵-18 = 14.
• the rest of the team will play the round 1. In addition to this there will be 16 teams which are participating in the round 2 to in the round 3 there will be a teams in the round 4 there will be 4 teams and in the final round there will be one team winning out of the two teams

Answer 2

$\Huge \orange{ \underline{ \underline{ \mathfrak{ \color{red}{Solution \: \: \: :-}}}}}$

$\huge \sf {2}^{5} - 18 = 14$