draw graph and find zeros
x2 +12x + 35
x2 + 4x + 4
plssss fast
Answers
Answered by
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Heya !!!
This is your answer.
Given :-
x² + 12x + 35 = 0
We have to look for two numbers a and b such that a+b = 12 and a×b= 35.
By looking at the prime factors of 35....
35 = 5×7.
We get a and b as 5 and 7.
So......
x² +12x + 35 = 0.
x² +7x + 5x + 35 = 0.
x (x +7) +5 (x +7) = 0.
(x+5)(x+7) = 0.
Comparing with 0,
x + 5 = 0 or x + 7 = 0
x = -5 or x = -7.
Hence, the two zeroes of given polynomial are-7 and -5.
Next.........
Given :-
x² + 4x + 4 = 0.
We have to look for two numbers a and b such that a+b = 4 and a×b= 4.
By looking at the prime factors of 4....
4 = 2×2.
We get a and b as 2 and 2.
So.......
x² + 4x + 4 = 0.
x² + 2x + 2x + 4 = 0
x ( x + 2) +2 (x+2). = 0.
(x +2)(x+2) = 0.
Comparing with 0,
x + 2 = 0 or x + 2 = 0.
x = -2 or x = -2.
Hence, the two zeroes of given polynomial are -2 and -2
Hope it helps
This is your answer.
Given :-
x² + 12x + 35 = 0
We have to look for two numbers a and b such that a+b = 12 and a×b= 35.
By looking at the prime factors of 35....
35 = 5×7.
We get a and b as 5 and 7.
So......
x² +12x + 35 = 0.
x² +7x + 5x + 35 = 0.
x (x +7) +5 (x +7) = 0.
(x+5)(x+7) = 0.
Comparing with 0,
x + 5 = 0 or x + 7 = 0
x = -5 or x = -7.
Hence, the two zeroes of given polynomial are-7 and -5.
Next.........
Given :-
x² + 4x + 4 = 0.
We have to look for two numbers a and b such that a+b = 4 and a×b= 4.
By looking at the prime factors of 4....
4 = 2×2.
We get a and b as 2 and 2.
So.......
x² + 4x + 4 = 0.
x² + 2x + 2x + 4 = 0
x ( x + 2) +2 (x+2). = 0.
(x +2)(x+2) = 0.
Comparing with 0,
x + 2 = 0 or x + 2 = 0.
x = -2 or x = -2.
Hence, the two zeroes of given polynomial are -2 and -2
Hope it helps
Anonymous:
thank u so muchh
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