Draw graph between displacement and time, when the body is moving with [2] (a) Uniform velocity (b) Non-uniform velocity.
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Step-by-step explanation:
Let two points A and B on the slope of graph.
Draw two lines parallel to y-axis AC from point A, and BD from point B.
Let point D at the x-axis (time axis) is t2 and point C is t1.
Let AB meet at ‘v’ at y-axis, i.e. object is moving with a velocity, v.
Thus, distance or displacement by the object is equal to the area of the rectangle (shaded) ABCD.
Thus, Area of
ABCD=BD×DC
⇒s=v(t2–t1)
Since given object is moving with constant velocity along a straight line, thus displacement will be equal to distance covered.
Therefore, Distance or Displacement = velocity X time interval.
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