Question

draw it on graph .
The taxi fare in a city is as follows: for the first kilometer the fare is Rs. 8
and for the subsequent distance it is Rs. 5 per km, taking the distance covered
as x km and total fare as Rs. Y, write a linear equation for this information
and draw its graph.​

Answer 1

Answer:

Given,Total distance covered= x km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y= 5+3=8

When x= 2, then y= 10+3=13

[Table & graph are on the attachment]

Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.

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Hope this will help you.....

#100%sure ANSWER

Answer 2

Answer:

x 0 1 2

y 3 8 13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)

solution