Draw L MN such that m ∆LMN =90°hypotenuse =5cm l(MN)=8cm
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0
Answer:
if it's right 8 should be 3
and the diagram like this
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Answered by
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Answer:
We need to construct a △LMN with MN=6.3 cm, LM=3 cm and ∠L=90
0
The following are the steps of construction:-
1) Draw a line segment LM=3 cm.
2) Draw an arc of any suitable radius taking L as centre intersecting extended line segment LM at O and Q.
3) Draw arcs taking same radius and O,Q as centres to intersect at P. Join and extend LP to get a line at 90
∘
to LM.
4) Now, taking M as centre and 6.3 cm radius, draw an arc intersecting line through L at N.
Hence, △LMN is the required triangle, as shown in the figure above.
Step-by-step explanation:
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