Math, asked by prasantadutta2655, 5 hours ago

Draw L MN such that m ∆LMN =90°hypotenuse =5cm l(MN)=8cm

Answers

Answered by VedantPanchal27
0

Answer:

if it's right 8 should be 3

and the diagram like this

Attachments:
Answered by Ashii24
1

Answer:

We need to construct a △LMN with MN=6.3 cm, LM=3 cm and ∠L=90

0

The following are the steps of construction:-

1) Draw a line segment LM=3 cm.

2) Draw an arc of any suitable radius taking L as centre intersecting extended line segment LM at O and Q.

3) Draw arcs taking same radius and O,Q as centres to intersect at P. Join and extend LP to get a line at 90

to LM.

4) Now, taking M as centre and 6.3 cm radius, draw an arc intersecting line through L at N.

Hence, △LMN is the required triangle, as shown in the figure above.

Step-by-step explanation:

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