Math, asked by Shreya9603, 1 year ago

Draw ‘less than ogive’ and ‘more than ogive’ for the following distribution and hence find its
median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

Answers

Answered by gayatrikumari99sl
0

Answer:

48.33 is the required value of median .

Step-by-step explanation:

Explanation:

Given , Class interval : 20-30,30-40,40-50,50-60,60-70,70-80,80-90

Frequency : 10 , 8 ,12 ,24 , 6 ,25 ,15

Formula of Median = l + (\frac{(\frac{n}{2}-c.f )}{f} )h

l = lower limit

n = sum of total frequency

c.f = Cumulative frequency

h = difference between two consecutive term

f = highest frequency

Step 1:

Highest frequency = 24

Total frequency = 100

\frac{n}{2}  = 50                       (where n =100)

Check the c.f column which is just greater than 50  and it is 54 .So , the c.f is 54

Therefore , the median class (50-60)

L= lower limit 50

h = 10  

Now put the value in median formula which is

Median = l + (\frac{(\frac{n}{2}-c.f )}{f} )h

             =50 + (\frac{(50-54 )}{24} )10 = 50 + (\frac{-4 }{24} )10 = \frac{1160}{24}

            =48.33

Final answer :

Hence , the median is 48.33.

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Answered by mahajan789
0

Answer: Median is 48.33

Step-by-step explanation: Given :

Sr. No. Classes Frequency  Cumulative frequency

  1.     20-30          10                    10
  2.     30-40          8                      18
  3.     40-50          12                    30
  4.     50-60          24                   54
  5.     60-70          6                     60
  6.     70-80          25                   85
  7.     80-90          15                    100

Median = l+(\frac{\frac{n}{2}-c.f}{f})h, where

l = lower limit

n = sum of total frequency

c.f = Cumulative frequency

h = difference between two consecutive term

f = highest frequency

From the data, f= 24, so median class is 50-60, \therefore l =50

n=100,\therefore\frac{n}{2}=50, and h= 10.

cf > f is 54, so cf= 54

Putting the values in the formula,

Median=50+(\frac{\frac{100}{2}-54}{24})10=48.33

#SPJ2

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