Draw ‘less than ogive’ and ‘more than ogive’ for the following distribution and hence find its
median.
Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90
frequency 10 8 12 24 6 25 15
Answers
Answer:
48.33 is the required value of median .
Step-by-step explanation:
Explanation:
Given , Class interval : 20-30,30-40,40-50,50-60,60-70,70-80,80-90
Frequency : 10 , 8 ,12 ,24 , 6 ,25 ,15
Formula of Median =
l = lower limit
n = sum of total frequency
c.f = Cumulative frequency
h = difference between two consecutive term
f = highest frequency
Step 1:
Highest frequency = 24
Total frequency = 100
(where n =100)
Check the c.f column which is just greater than 50 and it is 54 .So , the c.f is 54
Therefore , the median class (50-60)
L= lower limit 50
h = 10
Now put the value in median formula which is
Median =
= =
=48.33
Final answer :
Hence , the median is 48.33.
Answer: Median is 48.33
Step-by-step explanation: Given :
Sr. No. Classes Frequency Cumulative frequency
- 20-30 10 10
- 30-40 8 18
- 40-50 12 30
- 50-60 24 54
- 60-70 6 60
- 70-80 25 85
- 80-90 15 100
Median = , where
l = lower limit
n = sum of total frequency
c.f = Cumulative frequency
h = difference between two consecutive term
f = highest frequency
From the data, f= 24, so median class is 50-60,
n=100,, and h= 10.
cf > f is 54, so cf= 54
Putting the values in the formula,
Median==48.33
#SPJ2