Question

Draw molecular orbital diagrams of O2- ,O ,O2+ Explain the magnetic behaviour of these

Answer 1

Answer:

electrons in bonding orbital)−(No. of electrons in anti−bonding orbital)

Bond order of N

2

=

2

10−4

=

2

6

=3⇒N≡N

Bond order of O

2

=

2

10−6

=

2

4

=2⇒O≡O

If orbitals contains unpaired electrons, it is paramagnetic. Otherwise diamagnetic.

N

2

does not have unpaired electrons. So, it is diamagnetic.

O

2

have 2 unpaired electrons. So, it is paramagnetic.

Answer 2

Answer:

[Nb−Na]/2=[10−6]/2=2. Therefore there is a double bond present as O=O.