Draw ΔPQR in which QR = 5.4 cm, ∠Q = 40° and PR = 6.2 cm
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Answer:
Step-by-step explanation:
Steps of construction of triangle PQR in which PQ + PR = 6.5 cm QR = 5.4 cm, ∠Q = 40° is as follows
Draw a line segment QR=5.4 cm,then with the help of protector,draw 40° angle at Q,Extend that line up to X.
Measure 6.5 cm with compass and draw an arc of 6.5cm on line QX.
Join X to R.Draw a perpendicular bisector of line XR.
The perpendicular bisector of XR on extension, meet QX at P.
Join P and R.
Construction of ∆PQR has been done.
On measurements from constructed figure you will find that
PQ + PR = 6.5
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