Question

Draw ∆PQR with PQ= 4cm , QR= 3.5cm and PR= 4cm. What type of triangle is this?

Answer 1

Answer:

hey mate here is your answer....

construct : Δ PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. Steps of construction: (a) Draw a line segment QR = 3.5 cm. (b) Taking Q as centre and radius 4 cm, draw an arc. (c) Similarly, taking R as centre and radius 4 cm, draw an another arc which intersects first arc at P. (d) Join PQ and PR. It is the required isosceles Δ PQR.Read more on Sarthaks.com - https://www.sarthaks.com/107258/draw-pqr-with-pq-4-cm-qr-3-5-cm-and-pr-4-cm-what-type-of-triangle-is-this.

hope it's helpful for you....

thanks

Answer 2

Step-by-step explanation:

1. Draw a line segment QR of lenght 3.5cm.

2. From Q, point P is at a distance of 4cm. So, with Q as centre, draw an arc of radius 4cm.

3. From R, point P is at a distance of 4cm. So, with R as centre, draw an arc of radius 4cm.

4. P has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as P. Join PQ and PR.

∆PQR is now ready.

This triangle is an isocclus triangle.