Draw QR = 10 cm. Describe a semicircle on diameter QR.
Mark a point P on the semicircle so that ZPQR = 40°.
(1) What is the measure of ZQPR? Give reason.
(ii) Measure and record PQ and PR.
40°
10 cm
R
(11) Find the values of sin 40°, cos 40° and tan 40° with the measure of sides of APQR.
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Answers
Answered by
3
Answer:
π(5
2
)
=
2
25π
cm
2
Area of semi circle with diameter PR
=
2
π(4
2
)
=8π cm
2
Area of semi circle with PQ diameter
=
2
π(3
2
)
=
2
9π
cm
2
Area of triangle PQR=
2
1
×6×8=24 cm
2
Area of shaded regions
=(8π+
2
9π
+24)−(
2
25π
)
=12.5π+24−12.5π
=24 cm
2
Step-by-step explanation:
hi friend it higher class answer
Answered by
2
Step-by-step explanation:
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