Question

draw radius of 2s orbital vs probability density ​

Answer 1

Answer:

Logic:

Radial distribution curve gives an idea about the electron density at a radial distance from the nucleus. The value of 4πr2ψ2 (radial probability density function) becomes zero at a nodal point, also known as a radial node.

The number of radial nodes for an orbital = n-l-1.

Where n = principal quantum number and l= azimuthal quantum number.

Solution:

Since n = 3 and l = 1 for the given atomic orbital (3p orbital), the number of radial nodes = 3-1-1 = 1.  

Hence the radial probability distribution curve should contain a trough representing a radial node.

There are two graphs showing this behavior. The correct one is option-3 since the position of principal maximum (largest peak) occurs at a greater distance. I mean the crest with greater height should be farther away from the nucleus when compared to the smaller crest

Explanation: