Physics, asked by laxminarayanauppari5, 5 months ago

Draw ray diagram to show the process of refraction of light at different curved surfaces

Answers

Answered by freethanks50
8

Draw ray diagram to show the process of refraction of light at different Draw ray diagram to show the process of refraction of light at different curved surfacescurved surfaDraw ray diagram to show the process of refraction of light at different curved surfacescesDraw ray diagram to show the process of refraction of light at different curved surfacesDraw ray diagram to show the process of refraction of light at different curved surfaces

Answered by prasanthyadav999
2

Answer:

Consider a convex lens (or concave lens) of absolute refractive index μ

2

to be placed in a rarer medium of absolute refractive index μ

1

.

Considering the refraction of a point object on the surface XP

1

Y, the image is formed at I

1

who is at a distance of V

1

.

CI

1

=P

1

I

1

=V

1

(as the lens is thin)

CC

1

=P

1

C

1

=R

1

CO=P

1

O=u

It follows from the refraction due to convex spherical surface XP

1

Y

−u

μ

1

+

v

1

μ

2

=

R

1

μ

2

−μ

1

..........(i)

The refracted ray from A suffers a second refraction on the surface XP

2

Y and emerges along BI. Therefore I is the final real image of O.

Here the object distance is

u=CI

1

≈P

2

I

1

=V

P

1

P

2

is very small

Let CI≈P

2

I=V

(Final image distance)

Let R

2

be radius of curvature of second surface of the lens.

It follows from refraction due to concave spherical surface from denser to rarer medium that

v

1

−μ

2

+

v

μ

1

=

R

2

μ

1

−μ

2

=

−R

2

μ

2

−μ

1

............(ii)

Adding (i)and(ii)

u

−μ

1

+

v

μ

2

=(μ

2

−μ

1

)(

R

1

1

R

2

1

)

or

μ

1

(

v

1

u

1

)=(μ

2

−μ

2

)(

R

1

1

R

2

1

)

But

v

1

u

1

=

f

1

and

μ

1

μ

2

Thus we get=

f

1

=(μ−1)(

R

1

1

R

2

1

)

solution

Answered By

toppr

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